Statements, negations, connectives, truth tables, equivalent statements,
De Morgan’s Laws, arguments, Euler diagrams
Part 1: Statements, Negations, and Quantified Statements
A statement is a sentence that is either true or false but not both simultaneously.
Ex: a. Paris
is the capital of France;
b. Edgar
Poe wrote the last episode of Monk.
Commands, questions, and
opinions, are not statements because they are neither true nor false.
Ex: a. Titanic is the greatest movie of all
time. (opinion)
b. Solve the
exercises 20 – 50.(command)
c. If I
start losing my memory, how will I know? (question)
In symbolic logic, we use
lowercase letters such as p, q, r,
and s to represent statements.
Ex: p: Paris is the capital of France;
q: Edgar Poe wrote the last
episode of Monk.
The negation
of a statement has a meaning that is opposite that of the original meaning.
The negation of a true statement is a false statement and the negation of a
false statement is a true statement
Ex: a. The
negation of the statement “Edgar Poe
wrote the last episode of Monk” can be
“Edgar Poe did not write the last episode of
Monk” or also “It is not true that
Edgar Poe wrote the last episode of Monk”
b. The negation of the statement “Today
is not raining” is “Today is raining”
or “It is not true that today is not raining”.
Symbolically,
the negation of a statement p is
denoted by ~p.
Ex: p: Today is Sunday;
~p: Today is
not Sunday.
The words
all, some, and no (or none) are
called quantifiers.
Ex:
Statements containing a quantifier:
All poets
are writers.
Some
people are bigots.
No math
books have pictures.
Some
students do not work hard.
Equivalent
Ways of Expressing Quantified Statements
|
||
Statement
|
Equivalent way to express it
|
Example
|
All A are B
|
There are no A that are no B
|
All teachers are trained;
|
There
are no teachers that are
|
||
not
trained.
|
||
Some A are B
|
There is at least one A that is
|
Some people like ice-cream;
|
in B
|
At
least one person likes ice-
|
|
cream.
|
||
No A are B
|
All A are not B
|
No car is running on the rail
|
train;
|
||
All the
cars are not running on
|
||
the
rail train.
|
||
Some A are not B
|
Not all A are B
|
Some students do not pass the
|
class;
|
||
Not all
of the students are
|
||
passing
the class.
|
All A are B
(There are no A that are no B)




Some A
are B
(There is at least one A that is in B)
No A are B. (All A are not B)

Some A
are not B (Not all A are B)
Here are some examples of
quantified statements:

Symbolically,
the universal statement “All A are B”
can be written as “ A are B”, or “ A B”.
The
existential statement “Some A are B”
can be written as “ so that ”
Ex: The mechanic told me, “All
piston rings were replaced.” I later learned that the mechanic never tells
the truth. What can we conclude?
Because
the mechanic never tells the truth, we can Conclude that the truth is the
negation of what I was told.
The negation of “All A are B” is “Some A are not B”. Thus, I can conclude that
Some piston rings were not replaced.
I can also correctly conclude
that:
At least one piston ring was not replaced.
Part 2: Compound Statements and Connectives
Simple
statements convey one idea with no connecting words.
Compound statements combine two or more simple statements using connectives. Connectives are words used to join simple
statements. Examples are: and, or, if…then, and if and only if.
If p and q are two simple statements, then
the compound statement “p and q” is symbolized by p
q. The compound statement formed by connecting statements with the word and is called a conjunction. The
symbol for and is .
Ex: Let p and q represent the following simple statements:
p: It is Sunday.
q: They are working.
The compound statement “It is
Sunday and they are working” can be
formally/symbolically expressed by “p q”.
The compound statement “It is
Sunday and they are not working” can be
formally/symbolically expressed by “p ~q”.
Common
English Expressions for p q
|
||
Symbolic Statement
|
English Statement
|
Example:
|
p: It is Sunday.
|
||
q: They are working.
|
||
p q
|
p and q
|
It is Sunday and they are
|
working.
|
||
p q
|
p but q
|
It is Sunday, but they are
|
working.
|
||
p q
|
p yet q
|
It is Sunday, yet they are
|
working.
|
||
p q
|
p nevertheless q
|
It is Sunday; nevertheless they
|
are
working.
|
The connective or can mean two different things.
Consider the statement “I visited New
York City or Houston, TX.”
This statement can mean (exclusive or) “I visited New York City or Houston, TX but not both.”
It can also mean (inclusive or) “I visited New York City or Houston, TX or both.”
Disjunction is a compound statement formed using the inclusive or represented by the symbol
.
Thus, “p or q or both” is symbolized by p q.
Ex: Let p and q represent the
following simple statements:
p: The student prepared for the
Test.
q: The student passed the Test.
The
statement “The student prepared for the
Test or the student passed the Test” can be written as “p q”.
The statement “The student prepared
for the Test or the student did not pass the Test” can be written as “p ~q”.
The compound statement “If p,
then q is symbolized by p q. This is called a conditional statement. The statement before the is called the antecedent.
The statement after the is called
the consequent.
Ex: This diagram shows a
relationship that can be expressed 3 ways:

All men
are mortal.
There
are no men that are not mortal.
|
Mortals
|
||
If a
person is a men, then that person is mortal.
|
|||
Men
|
p: It is freezing.
|
|||
q: It is cold.
|
|||
The statement “If
it is freezing then it is cold” can be written as “p
|
q”.
|
||
The
statement “If it is not cold then it is
not freezing” can be written as “~q ~p”.
|
|||
Common
English expressions for p q:
|
|||
Symbolic Statement
|
English Statement
|
Example:
|
|
p: It is freezing.
|
|||
q: It is cold.
|
|||
p q
|
If p then q
|
If it
is freezing then it is cold.
|
|
p q
|
q if p
|
It is
cold if it is freezing.
|
|
p q
|
p is
sufficient for q
|
Being freezing is sufficient to
|
|
be
cold.
|
|||
p q
|
q is
necessary for p
|
Being cold is necessary for
|
|
being
freezing.
|
|||
p q
|
p only if q
|
It is
freezing only if it is cold.
|
|
p q
|
Only if
q, p
|
Only if
it is cold is freezing.
|
Biconditional statements are conditional statements that are true if the statement is
still true when the antecedent and
consequent are reversed.
The compound statement “p if and only if q” (abbreviated as iff ) is symbolized by p q.
Common English Expressions for p q:
Symbolic Statement
|
English Statement
|
Example:
|
p: It is 4th of July;
|
||
q: It is the Independence Day.
|
||
p q
|
p if and
only if q
|
It is 4th of
July if and only if it is
|
the
Independence Day.
|
||
p q
|
q if and
only if p
|
It is the Independence Day if
|
and only if it is 4th of
July.
|
||
p q
|
If p
then q, and if q then p.
|
If is 4th of
July then is the
|
Independence Day, and if is the
|
||
Independence Day then is 4th of
|
||
July.
|
||
p q
|
p is
necessary and sufficient
|
Being 4th of
July is necessary
|
for q
|
and
sufficient for being the
|
|
Independence
Day.
|
q is
necessary and sufficient
|
Being the Independence Day is
|
|
for p
|
necessary and sufficient for
|
|
being 4th of
July.
|
Ex: Let p
and q represent the following simple
statements: p: She is laughing.
q: She is happy.
~(p q): “It is not true that she is laughing and is
happy”;
~p q: “She is not laughing and she is happy”;
~(p q): “She is neither laughing nor happy”
or “”It is not true that she is laughing
or is happy”
Expressing
Symbolic Statements with Parentheses in English
Symbolic Statement
|
Statements to Group Together
|
English Translation
|
(q
~p) ~r
|
q ~p
|
If q and not p, then not r.
|
q ( ~p
~r)
|
~p ~r
|
q, and if not p then not r.
|
Remark: When we translate the symbolic statement into English, the
simple statements in parentheses appear on the same side of the comma.
Ex: Let p, q, and r represent the following simple statements:
p: A student misses class.
q: A student studies.
r: A student fails.
a.
(q ~ p) ~ r: “If
a student studies and does not miss class, then the student does not fail.”
b.
q (~p ~r): “A student studies, and if the student does
not miss class, then the student does not fail.”
If a symbolic statement appears without parentheses, statements before
and after the most dominant connective should
be grouped.
The
dominance of connectives used in symbolic logic is defined in the following
order:
Most
dominant:
|
Biconditional
|
||||
Same
level of dominance: Conjunction
|
|||||
Disjunction
|
|||||
Conditional
|
|||||
Least
dominant:
|
Negation
|
~
|
|||
Statement
|
Most Dominant
|
Statements Meaning Clarified
|
Type of
|
||
Connective Highlighted
|
with Grouping Symbols
|
Statement
|
|||
in Red
|
|||||
p q
~r
|
p q
~r
|
p (q
~r)
|
Conditional
|
||
p q~r
|
p q~r
|
(p q)~r
|
Conditional
|
||
pqr
|
pqr
|
p(qr)
|
Biconditional
|
||
pqr
|
pqr
|
(pq)r
|
Biconditional
|
||
p ~qr
s
|
p ~qr
s
|
(p ~q)(r
s)
|
Conditional
|
||
p q
r
|
p q
r
|
The
meaning is ambiguous.
|
?
|
||
Ex: Let
p, q, and r represent the following simple statements.
|
|||||
p: I fail the course.
|
|||||
q: I study hard.
|
|||||
r: I pass the final.
|
|||||
a. “I do
not fail the course if and only if I study hard and I pass the final”
|
~p
(q r )
|
Part 3: Truth Tables for Negation, Conjunction, and Disjunction
Negation (not):
Opposite truth value from the statement.
p
|
~p
|
|
T
|
F
|
|
F
|
T
|
Conjunction (and):
Only true when both statements are true.
p
|
q
|
p q
|
T
|
T
|
T
|
T
|
F
|
F
|
F
|
T
|
F
|
F
|
F
|
F
|
Disjunction (or):
Only false when both statements are false.
p
|
q
|
p q
|
T
|
T
|
T
|
T
|
F
|
T
|
F
|
T
|
T
|
F
|
F
|
F
|
Ex: Ex: Let p
and q represent the following
statements: p: 100 > 0
q: -4 < 15
Since
both statements are true, then p q is
true and p q is true. The statement ~p q will be false because ~p is false.
Ex:
Construct a truth table for ~(p q)
First list the simple statements on top and show all the possible truth
values. Second, make a column for p q
and fill in the truth values.
Third, construct one more column for ~(p q). The final column tells us that the statement is false only
when both p and q are true.
p
|
q
|
p q
|
~(p q)
|
T
|
T
|
T
|
F
|
T
|
F
|
F
|
T
|
F
|
T
|
F
|
T
|
F
|
F
|
F
|
T
|
A
compound statement that is always true is called a tautology. From the table, that means that on its column need to be
only Ts, no Fs.
Ex: p:
Brazosport College is a college. (true) q:
UHCL is an university. (true)
~(p q): “It is not true that BC is a college and UHCL
is an university”.
The compound statement ~(p q)
is not a tautology because on the last column it contains at least one F.
Ex: A
truth table for (~p q) ~q:
p q
|
~p
|
~p q
|
~q
|
(~p q)
~q
|
|
T
|
T
|
F
|
T
|
F
|
F
|
T
|
F
|
F
|
F
|
T
|
F
|
F
|
T
|
T
|
T
|
F
|
F
|
F
|
F
|
T
|
T
|
T
|
T
|
Ex: Construct a truth table for
the following statement:
a. I study
hard and ace the final, or I fail the course.
b. Suppose that you study hard, you do not ace the final and you fail the
course. Under these conditions, is this compound statement true or false?
First we represent our statements
as follows:
p: I study hard.
q: I ace the final.
r: I fail the course.
Then we write the statement “I
study hard and ace the final, or I fail the course” in symbolic form: .
Third, we build the table with
three entries (p, q and r):
p
|
q
|
r
|
p q
|
(p q) r
|
T
|
T
|
T
|
T
|
T
|
T
|
T
|
F
|
T
|
T
|
T
|
F
|
T
|
F
|
T
|
T
|
F
|
F
|
F
|
F
|
F
|
T
|
T
|
F
|
T
|
F
|
T
|
F
|
F
|
F
|
F
|
F
|
T
|
F
|
T
|
F
|
F
|
F
|
F
|
F
|
For part b, we have that p is
True, q is false and r is true, which means we need to look
on the row #3. The conclusion is T, so that, under these conditions, the
statement is True.
Not all the time we need to construct the truth table. We can determine
the truth value of a compound statement for a specific case in which the truth
values of the simple statements are known substituting the truth values of the
simple statements into the symbolic form of the compound statement and use the
appropriate definitions to determine the truth value of the compound statement.
Ex: On
the previous example, part b, we set the truth values: p is True, q is false and
r is true. So, the statement has in
fact the value .
Part 4: Truth Tables for the Conditional and the
Biconditional
Conditional
|
pq
|
||
p
|
q
|
pq
|
|
T
|
T
|
T
|
|
T
|
F
|
F
|
|
F
|
T
|
T
|
|
F
|
F
|
T
|
|
Remark: A
conditional is false only when the antecedent is true and the consequent is
false.
Ex: A truth table for ~q ~p:
p
|
q
|
~q
|
~p
|
~q ~p
|
T
|
T
|
F
|
F
|
T
|
T
|
F
|
T
|
F
|
F
|
F
|
T
|
F
|
T
|
T
|
F
|
F
|
T
|
T
|
T
|
Ex: A truth table for [( p q) ~ p] q:
p
|
q
|
p q
|
~p
|
( p
q) ~ p
|
[( p q)
~ p]q
|
T
|
T
|
T
|
F
|
F
|
T
|
T
|
F
|
T
|
F
|
F
|
T
|
F
|
T
|
T
|
T
|
T
|
T
|
F
|
F
|
F
|
T
|
F
|
T
|








p q
pq and qp
|
|||
p
|
q
|
pq
|
|
T
|
T
|
T
|
|
T
|
F
|
F
|
|
F
|
T
|
F
|
|
F
|
F
|
T
|
|
The Biconditional is True only
when the component statements have the same value.
Ex: You receive a letter that states that you have been assigned a Prize
Entry Number – 88855566. If your number matches the winning pre-selected number
and you return the number before the deadline, you will win $1,000,000.00.
Suppose that your number does not match the winning pre-selected number,
you return the number before the deadline and only win a free issue of a
magazine. Under these conditions, can you sue the credit card company for
making a false claim?
Assign letters to the simple
statements in the claim;
p: Your
number matches the pre-selected number False
q: You
return the number before the deadline True
r: You win
the prize False
Write the
underlined claim in the letter in symbolic form: (p q) r.
Substitute the truth values for p,
q, and r to determine the truth value for the letter’s claim: (F T) F, so
we have F F which is True.
The
truth-value analysis indicates that you cannot sue the credit card company for
making a false claim.
Part 5: Equivalent Statements and Variation of Conditional Statements
Equivalent compound statements are made up of the same simple statements and have the same corresponding truth values for
all true-false combinations of these simple statements.
If a compound statement is true, then its equivalent statement must also
be true. If a compound statement is false, its equivalent statement must also
be false.
Using the truth tables, the corresponding columns for the two statements
must be identical. The symbol which is used to show an equivalence is .
Ex: Show
that p ~q and ~p ~q are equivalent.
First we construct a truth table
and see if the corresponding truth values are the same:
p
|
q
|
~q
|
p ~q
|
~p
|
~p ~q
|
||||
T
|
T
|
F
|
T
|
F
|
T
|
||||
T
|
F
|
T
|
T
|
F
|
T
|
||||
F
|
T
|
F
|
F
|
T
|
F
|
||||
F
|
F
|
T
|
T
|
T
|
T
|
||||
The two
shaded columns are identical, so the statements are equivalent. We write this p ~q ~p
~q.
Ex: Show that p
|
q
|
~q ~p.
|
|||||||||
p
|
q
|
p q
|
~p
|
~q
|
~q ~p
|
||||||
T
|
T
|
T
|
F
|
F
|
T
|
||||||
T
|
F
|
F
|
F
|
T
|
F
|
||||||
F
|
T
|
T
|
T
|
F
|
T
|
||||||
F
|
F
|
T
|
T
|
T
|
T
|
||||||
The two shaded columns are
identical, so the statements are equivalent
The statement ~q ~p is called the contrapositive of the conditional p q.
They are logical equivalent.
Ex: Write the equivalent contrapositive for the statement “If you live in Houston, then you live in
Texas”.
p: You live in Houston.
|
|
q: You live in Texas.
|
|
If you live in Houston, then you live in Texas:
|
p q.
|
The
contrapositive is in symbolic form:
|
~q~p,
|
so that we can write it as an English statement: “If you do not live in Texas, then you do not live in Houston”.
Variations
of the Conditional Statement
|
||||
Name
|
Symbolic Form
|
English Translation
|
||
Conditional
|
p
|
q
|
If p,
then q.
|
|
Converse
|
q
|
p
|
If q,
then p.
|
|
Inverse
|
~p
|
~q
|
If not p,
then not q.
|
|
Contrapositive
|
~
|
~p
|
If not q,
then not p.
|
Practice Ex: Show that only the contrapositive is logical equivalent
with the conditional p q.
Practice
Ex: Show that Converse and Inverse are equivalent.
Ex: The statement “If it’s
freezing then is cold” can be written p q,
where
|
p:
|
It’s
freezing
|
q:
|
It’s
cold.
|
|
Converse:
|
p is “If it’s cold then is freezing”
|
|
Inverse:
|
~p
|
~q is “If it’s not freezing then is not cold”
|
Contrapositive: ~
|
~p is “If it’s not
cold then is not freezing”
|
Part 6: Negations of Conditional Statements and De
Morgan’s Laws
q)
|
p ~q.
|
|||||||
p
|
q
|
p
|
q
|
~(p q)
|
~q
|
p ~q.
|
||
T
|
T
|
T
|
F
|
F
|
F
|
|||
T
|
F
|
F
|
T
|
T
|
T
|
|||
F
|
T
|
T
|
F
|
F
|
F
|
|||
F
|
F
|
T
|
F
|
T
|
F
|

The negation of a conditional
statement can be expressed in the following way:
~(p q) p ~q.
Ex: The negation of the statement
“If too much homework is given, a class
should not be taken”
can be formed using:
p: Too much
homework is given,
q: A class
should be taken.
The
symbolic form is p ~q. The negation of p ~q is p ~(~ q) which simplifies to p q.
Translating this one into English we have: “Too much homework is given and a class should be taken.”
De Morgan’s Laws:
1.
|
~(p q)
|
~p ~q;
|
2.
|
~(p q)
|
~p ~q;
|
Ex: The first law is shown in the
truth table below.
p
|
q
|
p q
|
~(p q)
|
~p
|
~q
|
~p ~q
|
||
T
|
T
|
T
|
F
|
F
|
F
|
F
|
||
T
|
F
|
F
|
T
|
F
|
T
|
T
|
||
F
|
T
|
F
|
T
|
T
|
F
|
T
|
||
F
|
F
|
F
|
T
|
T
|
T
|
T
|
||
Practice Ex: Prove the second De
Morgan’s Law.
Ex: a. The
statement is given: “All students do
homework on weekends and I do not”
The
negation is: “Some students do not do
homework on weekends or I do”
b. The
statement is given: “Some college
professors are entertaining lecturers or I’m
bored.”
The
negation is: “No college professors are
entertaining lecturers and I’m not bored.”
Part 7: Arguments and Truth Tables
An Argument consists of two parts:
Conclusion:
the result determined by the truth of the premises.
If the conclusion is true whenever the premises are assumed to be true
then it is a valid argument. An invalid argument is also called a fallacy
Truth tables can be used to test
validity:
1. Use a
letter to label each statement in the argument;
2. Express
the premises and the conclusion symbolically;
3. Construct
the truth table and plot the conclusion on the last column;
4.
Check each row were all the
premises are True; if all of the corresponding true values on the last column
are also Ts, then the argument is valid; otherwise, is invalid.
Ex: If Mr. Teacher is explaining the lesson, then we all pass the Exam.
On the next Exam we all passed it.
Building the argument: If Mr. Teacher is explaining the lesson, then we
all pass the Exam. On the next Exam we all passed it. Therefore, if Mr. Teacher
explains the lesson, we all pass the Exam.
p: Mr.
Teacher is explaining the lesson;
q: We all
pass the exam
We
write these symbolically:
|
p
|
q
|
(Premise
1)
|
|
q
|
(Premise
2)
|
|||
p
|
(Conclusion)
|
The
table is:
|
|||||
Premise
2
|
Premise 2
|
Conclusion
|
|||
p
|
q
|
p q
|
p
|
||
T
|
T
|
T
|
T
|
||
T
|
F
|
F
|
T
|
||
F
|
T
|
T
|
F
|
||
F
|
F
|
T
|
F
|

Standard Forms of Arguments
Ex: Determine
whether this argument is valid or invalid: “There is no need for makeup because if there is an absence then there is
a need for makeup but there is no absence.”
p: There is an absence
|
||||
q: There is a need for makeup.
|
||||
Expressed
symbolically:
|
||||
If
there is an absence then there is need for makeup
|
p q
|
|||
There
is no absence.
|
.
|
~p
|
||
Therefore,
there is no need for makeup.
|
~q
|
The argument is in the form of
the fallacy of the inverse and is therefore, invalid.
Part 8: Arguments and Euler Diagrams
An Euler diagram is a technique for determining the validity of
arguments whose premises contain the words all, some, and no.

Euler Diagrams and Arguments:
1. Make an
Euler diagram for the first premise.
2. Make an
Euler diagram for the second premise on top of the one for the first premise.
3.
The argument is valid if and only
if every possible diagram illustrates the conclusion of the argument. If there
is even one possible diagram that contradicts the conclusion, this
indicates that the conclusion is not true in every case, so the argument is
invalid.
Ex:
|
Premise
1:
|
All
students who arrive late cannot take the test.
|
Premise
2:
|
All
students who cannot take the test are ineligible for a passing grade.
|
|
Conclusion:
|
Therefore, all students who arrive late are ineligible
for a passing grade.
|
Ineligible for a passing grade
|
||||
Cannot take test
|
Cannot take
test
|
|||

Since there is only one possible diagram, and it illustrates the
argument’s conclusion the argument is valid.
Premise
1:
|
All
cars are expensive.
|
|
Premise
2:
|
All
machines are expensive.
|
|
Conclusion:
|
Therefore, all cars are machines.
|

Are expensive
Cars
Adding “All machines are
expensive” can be done in four ways:
Are expensive
|
Are expensive
|
Are expensive
|
Are
expensive
|
||||||||||||||||||
Machines
|
Cars
|
||||||||||||||||||||
Cars
|
Cars
|
Machines
|
|||||||||||||||||||
Machines
|
Cars
|
Machines
|
|||||||||||||||||||

Not all
diagrams illustrate the argument’s conclusion that “All cars are machines.”
(The first two diagrams do not). The argument is invalid.
Ex: Premise
1: All
people are mortal.
Premise 2: Some mortals are cats.
Conclusion: Therefore, some people are cats.

Cats
The dot in the region of intersection shows that at least one mortal is
a cat. The diagram does not show the “people” and “cats” circle intersecting
with a dot in the region of intersection.
The argument is valid if and only if every possible diagram illustrates
the conclusion of the argument. The argument’s conclusion is: Some people are cats. The diagram does
not show the “people” circle and the “cats” circle intersecting with a dot in
the region of intersection. The conclusion does not follow from the premises.
The argument is invalid.